Under normal circumstances, motorcycles are crashed in the corners, and cars are turned outwards if they turn from corners. Why is this?
To understand this problem, we first need to know what is circular motion. The particle moves on a circle with a radius of the center r at a certain point, that is, the motion whose trajectory is a circle when the particle moves is called "circular motion". It is one of the most common curve movements. For example, the rotor of the motor, the wheel, the pulley, and the like are all in a circular motion. In circular motion, the most common and simplest is a uniform circular motion. The circular motion provides the acceleration required for the moving object with centripetal force. This centripetal force pulls the moving object toward the center point of the circular trajectory. If there is no centripetal force, the object will move linearly following Newton's first law. Even if the object rate is constant, the speed direction of the object is constantly changing. That is, in a uniform circular motion, the linear velocity changes (direction), and the angular velocity does not change.
With this in mind, let's look at the force analysis of a car at a constant corner. When turning a car, the car uses the "sliding angle of the tire to generate steering force" to drive the car to turn, so when the steering wheel turns to the direction of turning, the car body will start to turn in the direction of turning, but because of the centrifugal force on the body There will be an impact, so the body will tilt towards the outside of the steering.
In contrast, motorcycle tires are "using the camber's camber angle to produce lateral force", which is called the "extroverted thrust" force to drive the car to turn, then the motorcycle body will turn to want to turn The direction is tilted and then turned. Therefore, compared with the tire for automobiles, the tire shape of the motorcycle is circular in order to obtain a large angle of camber angle and a small radius of the tire cross section.